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3x^2-8x-1625=0
a = 3; b = -8; c = -1625;
Δ = b2-4ac
Δ = -82-4·3·(-1625)
Δ = 19564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19564}=\sqrt{4*4891}=\sqrt{4}*\sqrt{4891}=2\sqrt{4891}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{4891}}{2*3}=\frac{8-2\sqrt{4891}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{4891}}{2*3}=\frac{8+2\sqrt{4891}}{6} $
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